MATH SOLVE

4 months ago

Q:
# n the figure, 2004-02-04-06-00_files/i0250000.jpg. If the ratio of the perimeter of to that of is 3:2 and the sum of the perimeters of the two triangles is 110, find the perimeter of each triangle.A.perimeter of = 66perimeter of = 44B.perimeter of = 73perimeter of = 37C.perimeter of = 37perimeter of = 73D.perimeter of = 44perimeter of = 66

Accepted Solution

A:

I assume you needed to add the diagram. However, I'll assume that we have triangle 1 and triangle 2 and solve the problem.

You can then follow the same steps on the triangles you have.

Let perimeter of triangle 1 be p1 and that of triangle 2 be p2

First, we know that the ratio between p1 : p2 is 3:2, this means that:

p1/p2 = 3/2

p1 = (3/2) p2 .............> equation I

We also know that the sum of perimeters is 110, this means that:

p1 + p2 = 110 .........> equation II

Substitute by equation I in equation II as follows:

(3/2) p2 + p2 = 110

(5/2) p2 = 110

p2 = 44

Substitute by p2 in equation I to get p1 as follows:

p1 = (3/2) (44) = 66

Therefore:

perimeter of triangle 1 = p1 = 66

perimeter of triangle 2 = p2 = 44

You can then follow the same steps on the triangles you have.

Let perimeter of triangle 1 be p1 and that of triangle 2 be p2

First, we know that the ratio between p1 : p2 is 3:2, this means that:

p1/p2 = 3/2

p1 = (3/2) p2 .............> equation I

We also know that the sum of perimeters is 110, this means that:

p1 + p2 = 110 .........> equation II

Substitute by equation I in equation II as follows:

(3/2) p2 + p2 = 110

(5/2) p2 = 110

p2 = 44

Substitute by p2 in equation I to get p1 as follows:

p1 = (3/2) (44) = 66

Therefore:

perimeter of triangle 1 = p1 = 66

perimeter of triangle 2 = p2 = 44